X^2+300x-6400=0

Solution for X^2+300x-6400=0 equation:

X^2+300X-6400=0

a = 1; b = 300; c = -6400;
Δ = b2-4ac
Δ = 3002-4·1·(-6400)
Δ = 115600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{115600}=340$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-340}{2*1}=\frac{-640}{2}
=-320
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+340}{2*1}=\frac{40}{2}
=20
$